Interface InviteGroupCallParticipantResultUserAlreadyParticipant

The user can't be invited because they are already a participant of the call. Subtype of InviteGroupCallParticipantResult.

interface InviteGroupCallParticipantResultUserAlreadyParticipant {
    @type: "inviteGroupCallParticipantResultUserAlreadyParticipant";
}

Properties

@type

Properties

@type

@type: "inviteGroupCallParticipantResultUserAlreadyParticipant"

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@type